What is (\partial)/(\partial x)(3x^2-6x+3y^2) ?

The answer to (\partial)/(\partial x)(3x^2-6x+3y^2) is 6x-6

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(\partial)/(\partial x)(3x^2-6x+3y^2)

\frac{\partial}{\partial x} (3 x^{2} - 6 x + 3 y^{2})

6 x - 6

Solution steps

\frac{\partial}{\partial x} (3 x^{2} - 6 x + 3 y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3 x^{2}) - \frac{\partial}{\partial x} (6 x) + \frac{\partial}{\partial x} (3 y^{2})

\frac{\partial}{\partial x} (3 x^{2}) = 6 x

\frac{\partial}{\partial x} (6 x) = 6

\frac{\partial}{\partial x} (3 y^{2}) = 0

= 6 x - 6 + 0

Simplify

= 6 x - 6

\int x^{2} e d x

sin (100 \cdot t)

8 y^{^{''}} - 8 y^{^{'}} + 52 y = 0

f (x) = \frac{x ^{2} + 1}{x}

n = 1 \sum \infty \frac{5}{n ( n + 2 )}

What is (\partial)/(\partial x)(3x^2-6x+3y^2) ?
The answer to (\partial)/(\partial x)(3x^2-6x+3y^2) is 6x-6