What is the derivative of x+e^{-x} ?

The derivative of x+e^{-x} is 1-e^{-x}

What is the first derivative of x+e^{-x} ?

The first derivative of x+e^{-x} is 1-e^{-x}

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\frac{d}{d x} (x + e^{- x})

1 - e^{- x}

Solution steps

\frac{d}{d x} (x + e^{- x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (e^{- x})

\frac{d x}{d x} = 1

\frac{d}{d x} (e^{- x}) = - e^{- x}

= 1 - e^{- x}

\frac{\partial}{\partial y} (3 x^{2} y^{4})

\frac{d}{d x} (\frac{x - 2}{x - 2})

x \to 0 lim (sin (- \frac{1}{x}))

f (x) = x^{3} - 3 x^{2} + 2

\frac{d y}{d t} = \frac{( t e ^{t} )}{y 5 + y ^{2}}

What is the derivative of x+e^{-x} ?
The derivative of x+e^{-x} is 1-e^{-x}
What is the first derivative of x+e^{-x} ?
The first derivative of x+e^{-x} is 1-e^{-x}