What is the tangent of f(x)= 8/x ,\at x=2 ?

The tangent of f(x)= 8/x ,\at x=2 is y=-2x+8

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tangent of f(x)= 8/x ,\at x=2

tangent of

f (x) = \frac{8}{x}, at x = 2

y = - 2 x + 8

Solution steps

Find the tangent point:

(2, 4)

Find the slope of

f (x) = \frac{8}{x} : \frac{df ( x )}{d x} = - \frac{8}{x ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 2

Find the line with slope m=

- 2

and passing through

(2, 4) : y = - 2 x + 8

y = - 2 x + 8

\int \frac{7 x ^{2} + 13 x}{x ^{3} + x ^{2} - x - 1} d x

\frac{\partial}{\partial x} (6 x^{\frac{1}{3}} y^{\frac{2}{3}})

\frac{d}{d a} (\frac{cos ^{2} ( a )}{sin ( a ) - 1})

f (x) = x^{4} + 4 x^{2} - x, (1, 4)

\int \frac{x ^{2}}{x ^{2} + 16} d x

What is the tangent of f(x)= 8/x ,\at x=2 ?
The tangent of f(x)= 8/x ,\at x=2 is y=-2x+8