What is the limit as x approaches infinity of-1^xx ?

The limit as x approaches infinity of-1^xx is -infinity

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limit as x approaches infinity of-1^xx

x \to \infty lim (- 1^{x} x)

- \infty

Solution steps

x \to \infty lim (- 1^{x} x)

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= - x \to \infty lim (1^{x} x)

x \to a lim [f (x) \cdot g (x)] = x \to a lim f (x) \cdot x \to a lim g (x)

With the exception of indeterminate form

= - x \to \infty lim (1^{x}) \cdot x \to \infty lim (x)

x \to \infty lim (1^{x}) = 1

x \to \infty lim (x) = \infty

= - 1 \cdot \infty

Apply Infinity Property:

- c \cdot \infty = - \infty

= - \infty

\frac{d}{d x} (4 sin^{5} (x))

\int (1 + \frac{1}{2 x}) d x

\frac{x}{1 + x ^{2}}

\frac{\partial}{\partial y} (sin (x^{2} + x y))

y^{^{''}} - y = 18 t

What is the limit as x approaches infinity of-1^xx ?
The limit as x approaches infinity of-1^xx is -infinity