What is the derivative of (x^2+x^3^4) ?

The derivative of (x^2+x^3^4) is 4(x^2+x^3)^3(2x+3x^2)

What is the first derivative of (x^2+x^3^4) ?

The first derivative of (x^2+x^3^4) is 4(x^2+x^3)^3(2x+3x^2)

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\frac{d}{d x} ((x^{2} + x^{3})^{4})

4 (x^{2} + x^{3})^{3} (2 x + 3 x^{2})

Solution steps

\frac{d}{d x} ((x^{2} + x^{3})^{4})

Apply the chain rule:

4 (x^{2} + x^{3})^{3} \frac{d}{d x} (x^{2} + x^{3})

= 4 (x^{2} + x^{3})^{3} \frac{d}{d x} (x^{2} + x^{3})

\frac{d}{d x} (x^{2} + x^{3}) = 2 x + 3 x^{2}

= 4 (x^{2} + x^{3})^{3} (2 x + 3 x^{2})

\int 3 tan^{2} (x) sec^{3} (x) d x

\frac{d}{d x} (ln x^{2} + 9)

x \to - 1 lim (\frac{1}{x})

y = \frac{f ( x )}{x ^{7}}

x^{2} y^{^{''}} + 4 x y^{^{'}} - 4 y = 0

What is the derivative of (x^2+x^3^4) ?
The derivative of (x^2+x^3^4) is 4(x^2+x^3)^3(2x+3x^2)
What is the first derivative of (x^2+x^3^4) ?
The first derivative of (x^2+x^3^4) is 4(x^2+x^3)^3(2x+3x^2)