What is the derivative of a^x-4^x ?

The derivative of a^x-4^x is a^xln(a)-ln(2)*2^{2x+1}

What is the first derivative of a^x-4^x ?

The first derivative of a^x-4^x is a^xln(a)-ln(2)*2^{2x+1}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (a^{x} - 4^{x})

a^{x} ln (a) - ln (2) \cdot 2^{2 x + 1}

Solution steps

\frac{d}{d x} (a^{x} - 4^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (a^{x}) - \frac{d}{d x} (4^{x})

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

\frac{d}{d x} (4^{x}) = ln (2) \cdot 2^{2 x + 1}

= a^{x} ln (a) - ln (2) \cdot 2^{2 x + 1}

x \to - 1 lim (2 x^{2} - 5 x - 1)

n = 0 \sum \infty \frac{4}{3 ^{n}}

\frac{d}{d x} (a x + b x + a y (x) + b y (x))

\int 3 sec^{6} (x) d x

\frac{\partial}{\partial y} (\frac{8 x}{4 x ^{2} + 5 y ^{2}})

What is the derivative of a^x-4^x ?
The derivative of a^x-4^x is a^xln(a)-ln(2)*2^{2x+1}
What is the first derivative of a^x-4^x ?
The first derivative of a^x-4^x is a^xln(a)-ln(2)*2^{2x+1}