What is the derivative of 2x^4+4x^3+x ?

The derivative of 2x^4+4x^3+x is 8x^3+12x^2+1

What is the first derivative of 2x^4+4x^3+x ?

The first derivative of 2x^4+4x^3+x is 8x^3+12x^2+1

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\frac{d}{d x} (2 x^{4} + 4 x^{3} + x)

8 x^{3} + 12 x^{2} + 1

Solution steps

\frac{d}{d x} (2 x^{4} + 4 x^{3} + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{4}) + \frac{d}{d x} (4 x^{3}) + \frac{d x}{d x}

\frac{d}{d x} (2 x^{4}) = 8 x^{3}

\frac{d}{d x} (4 x^{3}) = 12 x^{2}

\frac{d x}{d x} = 1

= 8 x^{3} + 12 x^{2} + 1

f (x) = \frac{x ^{2}}{1 + 2 x}

x \to 0 lim (1 - \frac{x ^{2}}{6})

\frac{t d u}{d t} = t^{2} + 3 u, t > 0, H (5) = 100

\frac{d}{d x} (x - 2 e^{x})

x y^{^{'}} + y^{^{'}} - (x + 1) sin (x) + y = 0

What is the derivative of 2x^4+4x^3+x ?
The derivative of 2x^4+4x^3+x is 8x^3+12x^2+1
What is the first derivative of 2x^4+4x^3+x ?
The first derivative of 2x^4+4x^3+x is 8x^3+12x^2+1