What is the derivative of f(x)=sqrt(x)-6\sqrt[3]{x} ?

The derivative of f(x)=sqrt(x)-6\sqrt[3]{x} is 1/(2sqrt(x))-2/(x^{2/3)}

What is the first derivative of f(x)=sqrt(x)-6\sqrt[3]{x} ?

The first derivative of f(x)=sqrt(x)-6\sqrt[3]{x} is 1/(2sqrt(x))-2/(x^{2/3)}

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derivative of

f (x) = x - 6 3 x

\frac{1}{2 x} - \frac{2}{x ^{\frac{2}{3}}}

Solution steps

\frac{d}{d x} (x - 6 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x) - \frac{d}{d x} (6 3 x)

\frac{d}{d x} (x) = \frac{1}{2 x}

\frac{d}{d x} (6 3 x) = \frac{2}{x ^{\frac{2}{3}}}

= \frac{1}{2 x} - \frac{2}{x ^{\frac{2}{3}}}

\int 2 - 32 x^{3} d x

x^{2} - 5 x + 2

x \to 1 - lim (x^{2} + 2)

s (500)

\frac{\partial}{\partial x} ((ln (x^{2}))^{2})

What is the derivative of f(x)=sqrt(x)-6\sqrt[3]{x} ?
The derivative of f(x)=sqrt(x)-6\sqrt[3]{x} is 1/(2sqrt(x))-2/(x^{2/3)}
What is the first derivative of f(x)=sqrt(x)-6\sqrt[3]{x} ?
The first derivative of f(x)=sqrt(x)-6\sqrt[3]{x} is 1/(2sqrt(x))-2/(x^{2/3)}