What is (\partial)/(\partial x)(ycos(x)y) ?

The answer to (\partial)/(\partial x)(ycos(x)y) is -y^2sin(x)

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(\partial)/(\partial x)(ycos(x)y)

\frac{\partial}{\partial x} (y cos (x) y)

- y^{2} sin (x)

Solution steps

\frac{\partial}{\partial x} (y cos (x) y)

Simplify

y cos (x) y : y^{2} cos (x)

= \frac{\partial}{\partial x} (y^{2} cos (x))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y^{2} \frac{\partial}{\partial x} (cos (x))

Apply the common derivative:

\frac{\partial}{\partial x} (cos (x)) = - sin (x)

= y^{2} (- sin (x))

Simplify

= - y^{2} sin (x)

\frac{d}{d x} (sin (x^{2} y^{3}))

\frac{d}{d x} (lo g_{3} (x + 2))

y^{^{'}} = \frac{1}{e ^{- y} - x}

\int \frac{1}{( x - 2 ) ( x - 1 )} d x

\frac{7}{1 - t}

What is (\partial)/(\partial x)(ycos(x)y) ?
The answer to (\partial)/(\partial x)(ycos(x)y) is -y^2sin(x)