What is the limit as x approaches 2+of sqrt(8-x^3) ?

The limit as x approaches 2+of sqrt(8-x^3) is 0

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limit as x approaches 2+of sqrt(8-x^3)

x \to 2 + lim (8 - x^{3})

0

Solution steps

x \to 2 + lim (8 - x^{3})

Plug in the value

x = 2

= 8 - 2^{3}

Simplify

= 0

\frac{d}{d t} (3 t cos (t))

10 sin (x)

y = x, y = - x, x = 1, x = 4

x \to 0 + lim (x^{x^{6}})

y = x^{2} - 8, y = 7 x

What is the limit as x approaches 2+of sqrt(8-x^3) ?
The limit as x approaches 2+of sqrt(8-x^3) is 0