What is the limit as h approaches 1 of (h^3-1)/(h-1) ?

The limit as h approaches 1 of (h^3-1)/(h-1) is 3

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limit as h approaches 1 of (h^3-1)/(h-1)

h \to 1 lim (\frac{h ^{3} - 1}{h - 1})

3

Solution steps

h \to 1 lim (\frac{h ^{3} - 1}{h - 1})

Simplify

\frac{h ^{3} - 1}{h - 1} : h^{2} + h + 1

= h \to 1 lim (h^{2} + h + 1)

Plug in the value

h = 1

= 1^{2} + 1 + 1

Simplify

= 3

x \to 3 lim (- 3 x^{3} + 9 x + 5 x - 5)

x y^{^{'}} + 2 y = sin (x)

\frac{\partial}{\partial y} (8 y - 4 x)

\int_{0}^{1} x^{\frac{3}{2}} d x

y = e^{(4 x^{3} + 5)^{2}}

What is the limit as h approaches 1 of (h^3-1)/(h-1) ?
The limit as h approaches 1 of (h^3-1)/(h-1) is 3