What is the derivative of (x-3)^2*(1/2)+1 ?

The derivative of (x-3)^2*(1/2)+1 is x-3

What is the first derivative of (x-3)^2*(1/2)+1 ?

The first derivative of (x-3)^2*(1/2)+1 is x-3

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derivative of

(x - 3)^{2} \cdot (\frac{1}{2}) + 1

x - 3

Solution steps

\frac{d}{d x} ((x - 3)^{2} \frac{1}{2} + 1)

Simplify

(x - 3)^{2} \frac{1}{2} + 1 : \frac{( x - 3 ) ^{2}}{2} + 1

= \frac{d}{d x} (\frac{( x - 3 ) ^{2}}{2} + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{( x - 3 ) ^{2}}{2}) + \frac{d}{d x} (1)

\frac{d}{d x} (\frac{( x - 3 ) ^{2}}{2}) = x - 3

\frac{d}{d x} (1) = 0

= x - 3 + 0

Simplify

= x - 3

\frac{\partial}{\partial y} (- \frac{y}{x ^{2} + y ^{2}})

x \to 1 lim (lo g_{10} (x))

\int \frac{1}{u u ^{2} - a ^{2}} d u

ln (25 x)

\int_{8}^{11} \frac{y}{y ^{2} - 4 y - 5} d y

What is the derivative of (x-3)^2*(1/2)+1 ?
The derivative of (x-3)^2*(1/2)+1 is x-3
What is the first derivative of (x-3)^2*(1/2)+1 ?
The first derivative of (x-3)^2*(1/2)+1 is x-3