What is the tangent of f(x)= 1/(x+9),\at x=-7 ?

The tangent of f(x)= 1/(x+9),\at x=-7 is y=-1/4 x-5/4

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tangent of f(x)= 1/(x+9),\at x=-7

tangent of

f (x) = \frac{1}{x + 9}, at x = - 7

y = - \frac{1}{4} x - \frac{5}{4}

Solution steps

Find the tangent point:

(- 7, \frac{1}{2})

Find the slope of

f (x) = \frac{1}{x + 9} : \frac{df ( x )}{d x} = - \frac{1}{( x + 9 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{1}{4}

Find the line with slope m=

- \frac{1}{4}

and passing through

(- 7, \frac{1}{2}) : y = - \frac{1}{4} x - \frac{5}{4}

y = - \frac{1}{4} x - \frac{5}{4}

\frac{\partial}{\partial x} (3 y e^{4 x y} + 8 x)

\int \frac{3}{12 x - 1} d x

f (x) = \frac{x}{e ^{x}}

\frac{\partial}{\partial x} (x^{2} - x y + 8 y^{2})

\int_{0}^{1} 5 e^{- 2 x} d x

What is the tangent of f(x)= 1/(x+9),\at x=-7 ?
The tangent of f(x)= 1/(x+9),\at x=-7 is y=-1/4 x-5/4