What is the d/(dθ)(cos^2(θ)-sin^2(θ)) ?

The d/(dθ)(cos^2(θ)-sin^2(θ)) is -sin(2θ)*2

What is the first d/(dθ)(cos^2(θ)-sin^2(θ)) ?

The first d/(dθ)(cos^2(θ)-sin^2(θ)) is -sin(2θ)*2

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\frac{d}{d θ} (cos^{2} (θ) - sin^{2} (θ))

- sin (2 θ) \cdot 2

Solution steps

\frac{d}{d θ} (cos^{2} (θ) - sin^{2} (θ))

Simplify

cos^{2} (θ) - sin^{2} (θ) : cos (2 θ)

= \frac{d}{d θ} (cos (2 θ))

Apply the chain rule:

- sin (2 θ) \frac{d}{d θ} (2 θ)

= - sin (2 θ) \frac{d}{d θ} (2 θ)

\frac{d}{d θ} (2 θ) = 2

= - sin (2 θ) \cdot 2

\frac{d}{d t} (8 t e^{- t})

\int cos (\frac{y}{x}) d x

n = 0 \sum \infty (- \frac{1}{3})^{n}

(x y^{^{'}} - 1) ln (x) = 2 y

n = 0 \sum \infty \frac{1}{( 2 n + 3 ) ^{3}}

What is the d/(dθ)(cos^2(θ)-sin^2(θ)) ?
The d/(dθ)(cos^2(θ)-sin^2(θ)) is -sin(2θ)*2
What is the first d/(dθ)(cos^2(θ)-sin^2(θ)) ?
The first d/(dθ)(cos^2(θ)-sin^2(θ)) is -sin(2θ)*2