What is the derivative of e^{-2x+1} ?

The derivative of e^{-2x+1} is -2e^{-2x+1}

What is the first derivative of e^{-2x+1} ?

The first derivative of e^{-2x+1} is -2e^{-2x+1}

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\frac{d}{d x} (e^{- 2 x + 1})

- 2 e^{- 2 x + 1}

Solution steps

\frac{d}{d x} (e^{- 2 x + 1})

Apply the chain rule:

e^{- 2 x + 1} \frac{d}{d x} (- 2 x + 1)

= e^{- 2 x + 1} \frac{d}{d x} (- 2 x + 1)

\frac{d}{d x} (- 2 x + 1) = - 2

= e^{- 2 x + 1} (- 2)

Simplify

= - 2 e^{- 2 x + 1}

g (t) = \frac{3}{t}

f (x) = \frac{3}{x - 1}

y^{^{''}} + (\frac{2}{x}) y^{^{'}} = 2 x + 4

(x + y e^{\frac{y}{x}}) d x - x e^{\frac{y}{x}} d y = 0, y (1) = 0

\frac{d}{d x} (arccsc (x))

What is the derivative of e^{-2x+1} ?
The derivative of e^{-2x+1} is -2e^{-2x+1}
What is the first derivative of e^{-2x+1} ?
The first derivative of e^{-2x+1} is -2e^{-2x+1}