What is the derivative of me^{mx} ?

The derivative of me^{mx} is m^2e^{mx}

What is the first derivative of me^{mx} ?

The first derivative of me^{mx} is m^2e^{mx}

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\frac{d}{d x} (m e^{m x})

m^{2} e^{m x}

Solution steps

\frac{d}{d x} (m e^{m x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= m \frac{d}{d x} (e^{m x})

Apply the chain rule:

e^{m x} \frac{d}{d x} (m x)

= e^{m x} \frac{d}{d x} (m x)

\frac{d}{d x} (m x) = m

= m e^{m x} m

Simplify

m e^{m x} m : m^{2} e^{m x}

= m^{2} e^{m x}

x \to 0 lim (x 1 + \frac{1}{2})

\frac{\partial}{\partial v} (\frac{u - v}{2})

n = 0 \sum \infty \frac{n + 5}{5 ^{n}}

y^{'} = 0.1 (5 - y) y

\int \frac{3 ln ( x )}{x} d x

What is the derivative of me^{mx} ?
The derivative of me^{mx} is m^2e^{mx}
What is the first derivative of me^{mx} ?
The first derivative of me^{mx} is m^2e^{mx}