What is (\partial)/(\partial x)(-2y(-2x-y+6)) ?

The answer to (\partial)/(\partial x)(-2y(-2x-y+6)) is 4y

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(\partial)/(\partial x)(-2y(-2x-y+6))

\frac{\partial}{\partial x} (- 2 y (- 2 x - y + 6))

4 y

Solution steps

\frac{\partial}{\partial x} (- 2 y (- 2 x - y + 6))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 y \frac{\partial}{\partial x} (- 2 x - y + 6)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - 2 y (- \frac{\partial}{\partial x} (2 x) - \frac{\partial}{\partial x} (y) + \frac{\partial}{\partial x} (6))

\frac{\partial}{\partial x} (2 x) = 2

\frac{\partial}{\partial x} (y) = 0

\frac{\partial}{\partial x} (6) = 0

= - 2 y (- 2 - 0 + 0)

Simplify

= 4 y

\int_{- 8}^{0} \frac{1}{1 - x} d x

\frac{d}{d z} (\frac{y}{x ^{2} + y ^{2} + z ^{2}})

\int 9 arctan (x) d x

\frac{d}{d x} (8718 e (587 x))

\frac{x ^{2}}{x + 8}

What is (\partial)/(\partial x)(-2y(-2x-y+6)) ?
The answer to (\partial)/(\partial x)(-2y(-2x-y+6)) is 4y