What is the derivative of-1/(3x^3) ?

The derivative of-1/(3x^3) is 1/(x^4)

What is the first derivative of-1/(3x^3) ?

The first derivative of-1/(3x^3) is 1/(x^4)

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\frac{d}{d x} (- \frac{1}{3 x ^{3}})

\frac{1}{x ^{4}}

Solution steps

\frac{d}{d x} (- \frac{1}{3 x ^{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{1}{3} \frac{d}{d x} (\frac{1}{x ^{3}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - \frac{1}{3} \frac{d}{d x} (x^{- 3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - \frac{1}{3} (- 3 x^{- 3 - 1})

Simplify

- \frac{1}{3} (- 3 x^{- 3 - 1}) : \frac{1}{x ^{4}}

= \frac{1}{x ^{4}}

y = 30 e^{- 0.0000323 (1600)}

\frac{\partial}{\partial x} (tan (\frac{y}{x}))

∣ x ∣, x^{2}

\int (x^{11}) d x

\frac{d}{d x} (\frac{x}{( x - 4 ) ^{2}})

What is the derivative of-1/(3x^3) ?
The derivative of-1/(3x^3) is 1/(x^4)
What is the first derivative of-1/(3x^3) ?
The first derivative of-1/(3x^3) is 1/(x^4)