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Popular >

2xy+6x+(x^2-4)y^'=0

Solution

2 x y + 6 x + (x^{2} - 4) y^{^{'}} = 0

Solution

y = \frac{c _{1}}{x ^{2} - 4} - 3

Solution steps

2 x y + 6 x + (x^{2} - 4) y^{'} (x) = 0

Solve separable ODE:

y = \frac{c _{1}}{x ^{2} - 4} - 3

y = \frac{c _{1}}{x ^{2} - 4} - 3

Graph

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n = 1 \sum \infty \frac{1 ^{n}}{n + 2}

limit as x approaches 2-of cx^2+6x

x \to 2 - lim (c x^{2} + 6 x)

integral of (x^2+32x-16)/(x^3-16x)

\int \frac{x ^{2} + 32 x - 16}{x ^{3} - 16 x} d x

integral of (-3x+4)

\int (- 3 x + 4) d x

Frequently Asked Questions (FAQ)

What is the solution for 2xy+6x+(x^2-4)y^'=0 ?
The solution for 2xy+6x+(x^2-4)y^'=0 is y=(c_{1})/(x^2-4)-3