What is integral from 4 to 6 of f(x) ?

The answer to integral from 4 to 6 of f(x) is f*10

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integral from 4 to 6 of f(x)

\int_{4}^{6} f (x) d x

f \cdot 10

Solution steps

\int_{4}^{6} f x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= f \cdot \int_{4}^{6} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{4}^{6}

= f [\frac{x ^{2}}{2}]_{4}^{6}

Compute the boundaries:

10

= f \cdot 10

- \frac{1}{x + 1 ^{2}}

5 + 3 + x

f (x) = \frac{x - 1}{x ^{2} + 4}

x \to - 2 lim ((x + 4)^{2})

y = \frac{3 x}{x ^{2} - 6}, (3, 3)

What is integral from 4 to 6 of f(x) ?
The answer to integral from 4 to 6 of f(x) is f*10