What is the solution for (dy)/(dx)+1/x y=5x^2 ?

The solution for (dy)/(dx)+1/x y=5x^2 is y=(5x^3)/4+(c_{1})/x

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(dy)/(dx)+1/x y=5x^2

\frac{d y}{d x} + \frac{1}{x} y = 5 x^{2}

y = \frac{5 x ^{3}}{4} + \frac{c _{1}}{x}

Solution steps

\frac{d y}{d x} + \frac{1}{x} y = 5 x^{2}

Solve linear ODE:

y = \frac{5 x ^{3}}{4} + \frac{c _{1}}{x}

y = \frac{5 x ^{3}}{4} + \frac{c _{1}}{x}

\frac{d}{d x} (\frac{a + b x}{a - b x})

y^{^{'}} + 10 y = t + e^{- 5 t}

\frac{d}{d x} (x^{2} \cdot cos (x^{2}))

\int (e^{- x} + 4^{x}) d x

G (r) = r + 4 r

What is the solution for (dy)/(dx)+1/x y=5x^2 ?
The solution for (dy)/(dx)+1/x y=5x^2 is y=(5x^3)/4+(c_{1})/x