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Popular >

derivative of f(x)=(5x^3+6x^2+4)^8

Solution

derivative of

f (x) = (5 x^{3} + 6 x^{2} + 4)^{8}

Solution

8 (5 x^{3} + 6 x^{2} + 4)^{7} (15 x^{2} + 12 x)

Solution steps

\frac{d}{d x} ((5 x^{3} + 6 x^{2} + 4)^{8})

Apply the chain rule:

8 (5 x^{3} + 6 x^{2} + 4)^{7} \frac{d}{d x} (5 x^{3} + 6 x^{2} + 4)

= 8 (5 x^{3} + 6 x^{2} + 4)^{7} \frac{d}{d x} (5 x^{3} + 6 x^{2} + 4)

\frac{d}{d x} (5 x^{3} + 6 x^{2} + 4) = 15 x^{2} + 12 x

= 8 (5 x^{3} + 6 x^{2} + 4)^{7} (15 x^{2} + 12 x)

Graph

Popular Examples

tangent of y=sin(sin(x)),(2pi,0)tangent of

y = sin (sin (x)), (2 π, 0)

y^{''}+5y^'+4y=8x^2+6e^{-x}

y^{^{''}} + 5 y^{^{'}} + 4 y = 8 x^{2} + 6 e^{- x}

integral of xsin(1/10 x)

\int x sin (\frac{1}{10} x) d x

integral of sqrt(x+1)ln(x+1)

\int x + 1 ln (x + 1) d x

integral of 5x(2+3x^2)^8

\int 5 x (2 + 3 x^{2})^{8} d x

Frequently Asked Questions (FAQ)

What is the derivative of f(x)=(5x^3+6x^2+4)^8 ?
The derivative of f(x)=(5x^3+6x^2+4)^8 is 8(5x^3+6x^2+4)^7(15x^2+12x)
What is the first derivative of f(x)=(5x^3+6x^2+4)^8 ?
The first derivative of f(x)=(5x^3+6x^2+4)^8 is 8(5x^3+6x^2+4)^7(15x^2+12x)