What is the derivative of log_{7}(x^2+e^x-ln(ln(x))) ?

The derivative of log_{7}(x^2+e^x-ln(ln(x))) is (2x+e^x)/(ln(7)(x^2+e^x))-1/(xln(x))

What is the first derivative of log_{7}(x^2+e^x-ln(ln(x))) ?

The first derivative of log_{7}(x^2+e^x-ln(ln(x))) is (2x+e^x)/(ln(7)(x^2+e^x))-1/(xln(x))

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\frac{d}{d x} (lo g_{7} (x^{2} + e^{x}) - ln (ln (x)))

\frac{2 x + e ^{x}}{ln ( 7 ) ( x ^{2} + e ^{x} )} - \frac{1}{x ln ( x )}

Solution steps

\frac{d}{d x} (lo g_{7} (x^{2} + e^{x}) - ln (ln (x)))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (lo g_{7} (x^{2} + e^{x})) - \frac{d}{d x} (ln (ln (x)))

\frac{d}{d x} (lo g_{7} (x^{2} + e^{x})) = \frac{2 x + e ^{x}}{ln ( 7 ) ( x ^{2} + e ^{x} )}

\frac{d}{d x} (ln (ln (x))) = \frac{1}{x ln ( x )}

= \frac{2 x + e ^{x}}{ln ( 7 ) ( x ^{2} + e ^{x} )} - \frac{1}{x ln ( x )}

\frac{d}{d x} (25 - x^{2})

\frac{\partial}{\partial y} (2 x + y - 1)

3 t sin (π t)

\frac{d}{d x} (ln (tan (\frac{x}{2})))

x \to - 2 lim (\frac{1 - x ^{2}}{x + 2})

What is the derivative of log_{7}(x^2+e^x-ln(ln(x))) ?
The derivative of log_{7}(x^2+e^x-ln(ln(x))) is (2x+e^x)/(ln(7)(x^2+e^x))-1/(xln(x))
What is the first derivative of log_{7}(x^2+e^x-ln(ln(x))) ?
The first derivative of log_{7}(x^2+e^x-ln(ln(x))) is (2x+e^x)/(ln(7)(x^2+e^x))-1/(xln(x))