What is the derivative of 20+0.6sqrt(x) ?

The derivative of 20+0.6sqrt(x) is (0.3)/(sqrt(x))

What is the first derivative of 20+0.6sqrt(x) ?

The first derivative of 20+0.6sqrt(x) is (0.3)/(sqrt(x))

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\frac{d}{d x} (20 + 0.6 x)

\frac{0.3}{x}

Solution steps

\frac{d}{d x} (20 + 0.6 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (20) + \frac{d}{d x} (0.6 x)

\frac{d}{d x} (20) = 0

\frac{d}{d x} (0.6 x) = \frac{0.3}{x}

= 0 + \frac{0.3}{x}

Simplify

= \frac{0.3}{x}

\frac{e ^{3 x}}{x ^{6}}

\frac{\partial}{\partial x} (\frac{e ^{x}}{y + x ^{9}})

y^{^{'}} = \frac{( ( y - y ^{2} ) t )}{1 + t ^{2}}, y (0) = \frac{1}{2}

\int 2 t^{\frac{3}{2}} d t

\int \frac{9}{( x - 7 ) ( x + 2 )} d x

What is the derivative of 20+0.6sqrt(x) ?
The derivative of 20+0.6sqrt(x) is (0.3)/(sqrt(x))
What is the first derivative of 20+0.6sqrt(x) ?
The first derivative of 20+0.6sqrt(x) is (0.3)/(sqrt(x))