What is the first derivative of 1+4x^2 ?

The first derivative of 1+4x^2 is 8x

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derivative of 1+4x^2

\frac{d}{d x} (1 + 4 x^{2})

8 x

Solution steps

\frac{d}{d x} (1 + 4 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (4 x^{2})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (4 x^{2}) = 8 x

= 0 + 8 x

Simplify

= 8 x

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