What is the derivative of f(x)=x^4+2x ?

The derivative of f(x)=x^4+2x is 4x^3+2

What is the first derivative of f(x)=x^4+2x ?

The first derivative of f(x)=x^4+2x is 4x^3+2

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derivative of

f (x) = x^{4} + 2 x

4 x^{3} + 2

Solution steps

\frac{d}{d x} (x^{4} + 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) + \frac{d}{d x} (2 x)

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (2 x) = 2

= 4 x^{3} + 2

\frac{d ^{2}}{d x ^{2}} (e^{c o s (x)})

\int - \frac{1}{1 + 9 x ^{2}} d x

\int (2 x + 2)^{- 1} d x

\int - 5 x^{2} sin (π x) d x

\frac{1}{( x ^{2} - 1 ) ( x ^{2} + 5 x + 5 )}

What is the derivative of f(x)=x^4+2x ?
The derivative of f(x)=x^4+2x is 4x^3+2
What is the first derivative of f(x)=x^4+2x ?
The first derivative of f(x)=x^4+2x is 4x^3+2