What is (\partial)/(\partial x)(9xy+sin(y)) ?

The answer to (\partial)/(\partial x)(9xy+sin(y)) is 9y

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(\partial)/(\partial x)(9xy+sin(y))

\frac{\partial}{\partial x} (9 x y + sin (y))

9 y

Solution steps

\frac{\partial}{\partial x} (9 x y + sin (y))

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (9 x y) + \frac{\partial}{\partial x} (sin (y))

\frac{\partial}{\partial x} (9 x y) = 9 y

\frac{\partial}{\partial x} (sin (y)) = 0

= 9 y + 0

Simplify

= 9 y

\frac{\partial}{\partial x} (\frac{5 x + 8}{4 y + 1})

f (x) = (4 x)

\int_{0}^{2 π} sin^{2} (6 x) d x

x \to 3 lim (lo g_{3} (x))

What is (\partial)/(\partial x)(9xy+sin(y)) ?
The answer to (\partial)/(\partial x)(9xy+sin(y)) is 9y