What is the solution for y^'-y=10te^{2t},y(0)=1 ?

The solution for y^'-y=10te^{2t},y(0)=1 is y=10e^{2t}(t-1)+11e^t

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y^'-y=10te^{2t},y(0)=1

y^{^{'}} - y = 10 t e^{2 t}, y (0) = 1

y = 10 e^{2 t} (t - 1) + 11 e^{t}

Solution steps

y^{'} (t) - y = 10 t e^{2 t}

Solve linear ODE:

y = 10 e^{2 t} (t - 1) + 11 e^{t}

y = 10 e^{2 t} (t - 1) + 11 e^{t}

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What is the solution for y^'-y=10te^{2t},y(0)=1 ?
The solution for y^'-y=10te^{2t},y(0)=1 is y=10e^{2t}(t-1)+11e^t