What is the solution for 2y+(dy)/(dx)=y^2+1 ?

The solution for 2y+(dy)/(dx)=y^2+1 is y=-1/(x+c_{1)}+x/(x+c_{1)}+(c_{1})/(x+c_{1)}

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2y+(dy)/(dx)=y^2+1

2 y + \frac{d y}{d x} = y^{2} + 1

y = - \frac{1}{x + c _{1}} + \frac{x}{x + c _{1}} + \frac{c _{1}}{x + c _{1}}

Solution steps

2 y + \frac{d y}{d x} = y^{2} + 1

Solve separable ODE:

y = - \frac{1}{x + c _{1}} + \frac{x}{x + c _{1}} + \frac{c _{1}}{x + c _{1}}

y = - \frac{1}{x + c _{1}} + \frac{x}{x + c _{1}} + \frac{c _{1}}{x + c _{1}}

h (x) = \frac{3}{x ^{2}} + 10 x^{3} - 2 sin (3 x)

\int \frac{2 + 3 x}{x - 3} d x

ln (1 - 7 x), 0

\int \frac{2 x}{3} + 3 d x

\frac{1}{1 - x}, 14

What is the solution for 2y+(dy)/(dx)=y^2+1 ?
The solution for 2y+(dy)/(dx)=y^2+1 is y=-1/(x+c_{1)}+x/(x+c_{1)}+(c_{1})/(x+c_{1)}