What is the sum from n=1 to infinity of (1/2)^2 ?

The sum from n=1 to infinity of (1/2)^2 is diverges

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sum from n=1 to infinity of (1/2)^2

n = 1 \sum \infty (\frac{1}{2})^{2}

diverges

Solution steps

n = 1 \sum \infty (\frac{1}{2})^{2}

Every infinite sum of a non-zero constant diverges

= diverges

x^{^{''}} - 2 x^{^{'}} + x = 24 t^{2} e^{t}

f (x) = x^{8 x}

\int \frac{sec ^{2} ( 8 x )}{tan ( 8 x ) - 6} d x

\frac{d y}{d x} = x e^{x^{2} - 4}

n = 1 \sum \infty (- 8)^{- n}

What is the sum from n=1 to infinity of (1/2)^2 ?
The sum from n=1 to infinity of (1/2)^2 is diverges