What is the derivative of (9-x^2/((9+x^2)^2)) ?

The derivative of (9-x^2/((9+x^2)^2)) is -(2x(-x^2+27))/((x^2+9)^3)

What is the first derivative of (9-x^2/((9+x^2)^2)) ?

The first derivative of (9-x^2/((9+x^2)^2)) is -(2x(-x^2+27))/((x^2+9)^3)

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\frac{d}{d x} (\frac{9 - x ^{2}}{( 9 + x ^{2} ) ^{2}})

- \frac{2 x ( - x ^{2} + 27 )}{( x ^{2} + 9 ) ^{3}}

Solution steps

\frac{d}{d x} (\frac{9 - x ^{2}}{( 9 + x ^{2} ) ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 9 - x ^{2} ) ( 9 + x ^{2} ) ^{2} - \frac{d}{d x} ( ( 9 + x ^{2} ) ^{2} ) ( 9 - x ^{2} )}{( ( 9 + x ^{2} ) ^{2} ) ^{2}}

\frac{d}{d x} (9 - x^{2}) = - 2 x

\frac{d}{d x} ((9 + x^{2})^{2}) = 4 x (9 + x^{2})

= \frac{( - 2 x ) ( 9 + x ^{2} ) ^{2} - 4 x ( 9 + x ^{2} ) ( 9 - x ^{2} )}{( ( 9 + x ^{2} ) ^{2} ) ^{2}}

Simplify

\frac{( - 2 x ) ( 9 + x ^{2} ) ^{2} - 4 x ( 9 + x ^{2} ) ( 9 - x ^{2} )}{( ( 9 + x ^{2} ) ^{2} ) ^{2}} : - \frac{2 x ( - x ^{2} + 27 )}{( x ^{2} + 9 ) ^{3}}

= - \frac{2 x ( - x ^{2} + 27 )}{( x ^{2} + 9 ) ^{3}}

\frac{1}{sin ^{2} ( x )}

\int x^{2} 9 + x d x

\frac{x}{x ^{2} + 1}

(x^{2} + 1) \frac{d y}{d x} + 6 x (y - 1) = 0, y (0) = 8

\int (x + 6)^{4} d x

What is the derivative of (9-x^2/((9+x^2)^2)) ?
The derivative of (9-x^2/((9+x^2)^2)) is -(2x(-x^2+27))/((x^2+9)^3)
What is the first derivative of (9-x^2/((9+x^2)^2)) ?
The first derivative of (9-x^2/((9+x^2)^2)) is -(2x(-x^2+27))/((x^2+9)^3)