What is the first derivative of 16t^2 ?

The first derivative of 16t^2 is 32t

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derivative of 16t^2

derivative of

16 t^{2}

32 t

Solution steps

\frac{d}{d t} (16 t^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 16 \frac{d}{d t} (t^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 16 \cdot 2 t^{2 - 1}

Simplify

= 32 t

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