What is (\partial)/(\partial x)(r(θ,x)sin(θ)) ?

The answer to (\partial)/(\partial x)(r(θ,x)sin(θ)) is rsin(θ)(θ,1)

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(\partial)/(\partial x)(r(θ,x)sin(θ))

\frac{\partial}{\partial x} (r (θ, x) sin (θ))

r sin (θ) (θ, 1)

Solution steps

\frac{\partial}{\partial x} (r (θ, x) sin (θ))

Treat

r, θ

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= r sin (θ) \frac{\partial}{\partial x} (θ, x)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= r sin (θ) (θ, \frac{\partial}{\partial x} (x))

Apply the common derivative:

\frac{\partial}{\partial x} (x) = 1

= r sin (θ) (θ, 1)

x = 5, y = 5 x

\frac{sin ( 5 x )}{3 x}

\frac{\partial}{\partial x} (y^{2} - x^{2} - x^{3})

\int_{0}^{1} 2 1 - x^{2} d x

(x^{2} + 1) e^{x - 1}, 1

What is (\partial)/(\partial x)(r(θ,x)sin(θ)) ?
The answer to (\partial)/(\partial x)(r(θ,x)sin(θ)) is rsin(θ)(θ,1)