What is the integral from 1 to R of x^{-9/4} ?

The integral from 1 to R of x^{-9/4} is -4/(5R^{5/4)}+4/5

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integral from 1 to R of x^{-9/4}

\int_{1}^{R} x^{- \frac{9}{4}} d x

- \frac{4}{5 R ^{\frac{5}{4}}} + \frac{4}{5}

Solution steps

\int_{1}^{R} x^{- \frac{9}{4}} d x

Apply the Power Rule

: [- \frac{4}{5 x ^{\frac{5}{4}}}]_{1}^{R}

= [- \frac{4}{5 x ^{\frac{5}{4}}}]_{1}^{R}

Compute the boundaries:

- \frac{4}{5 R ^{\frac{5}{4}}} + \frac{4}{5}

= - \frac{4}{5 R ^{\frac{5}{4}}} + \frac{4}{5}

n = 1 \sum \infty \frac{1}{5 ^{n} + 7}

ln (7 - 3 x)

x^{2} y^{^{''}} + 3 x y^{^{'}} = 2

\int cos (u) d u

e^{8 t s i n (2 t)}

What is the integral from 1 to R of x^{-9/4} ?
The integral from 1 to R of x^{-9/4} is -4/(5R^{5/4)}+4/5