What is the integral of (26x^3-52x^2+7)/(x^2-2x) ?

The integral of (26x^3-52x^2+7)/(x^2-2x) is 13x^2-7(1/2 ln|x|-1/2 ln|x-2|)+C

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integral of (26x^3-52x^2+7)/(x^2-2x)

\int \frac{26 x ^{3} - 52 x ^{2} + 7}{x ^{2} - 2 x} d x

13 x^{2} - 7 (\frac{1}{2} ln ∣ x ∣ - \frac{1}{2} ln ∣ x - 2 ∣) + C

Solution steps

\int \frac{26 x ^{3} - 52 x ^{2} + 7}{x ^{2} - 2 x} d x

Long division

\frac{26 x ^{3} - 52 x ^{2} + 7}{x ^{2} - 2 x} : 26 x + \frac{7}{x ^{2} - 2 x}

= \int 26 x + \frac{7}{x ^{2} - 2 x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 26 x d x + \int \frac{7}{x ^{2} - 2 x} d x

\int 26 x d x = 13 x^{2}

\int \frac{7}{x ^{2} - 2 x} d x = - 7 (\frac{1}{2} ln ∣ x ∣ - \frac{1}{2} ln ∣ x - 2 ∣)

= 13 x^{2} - 7 (\frac{1}{2} ln ∣ x ∣ - \frac{1}{2} ln ∣ x - 2 ∣)

Add a constant to the solution

= 13 x^{2} - 7 (\frac{1}{2} ln ∣ x ∣ - \frac{1}{2} ln ∣ x - 2 ∣) + C

ln (9)

\int_{0}^{1} \frac{x}{( x ^{2} + 1 ) ^{3}} d x

y = \frac{1 + x ^{2}}{arccot ( x )}

\int_{- 2}^{0} π (2 x^{2} + 4 x + 3)^{2} d x

\frac{d}{d x} (72 x (6 x^{2} + 8)^{5})

What is the integral of (26x^3-52x^2+7)/(x^2-2x) ?
The integral of (26x^3-52x^2+7)/(x^2-2x) is 13x^2-7(1/2 ln|x|-1/2 ln|x-2|)+C