What is the derivative of y=x^2+x+8 ?

The derivative of y=x^2+x+8 is 2x+1

What is the first derivative of y=x^2+x+8 ?

The first derivative of y=x^2+x+8 is 2x+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

y = x^{2} + x + 8

2 x + 1

Solution steps

\frac{d}{d x} (x^{2} + x + 8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d x}{d x} + \frac{d}{d x} (8)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d x}{d x} = 1

\frac{d}{d x} (8) = 0

= 2 x + 1 + 0

Simplify

= 2 x + 1

\frac{d}{d x} (- \frac{3}{2} x^{5} + \frac{2}{5} x^{3} - \frac{1}{6} x^{2} - 4 x)

y = ln (\frac{x}{5 - x})

x \to \infty lim (3 - x^{2})

\frac{d}{d x} (\frac{x - 6}{x + 6})

f (θ) = 13 θ - 8 sin (θ)

What is the derivative of y=x^2+x+8 ?
The derivative of y=x^2+x+8 is 2x+1
What is the first derivative of y=x^2+x+8 ?
The first derivative of y=x^2+x+8 is 2x+1