What is the derivative of 8x^{-1} ?

The derivative of 8x^{-1} is -8/(x^2)

What is the first derivative of 8x^{-1} ?

The first derivative of 8x^{-1} is -8/(x^2)

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\frac{d}{d x} (8 x^{- 1})

- \frac{8}{x ^{2}}

Solution steps

\frac{d}{d x} (8 x^{- 1})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d x} (x^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 8 (- 1 \cdot x^{- 1 - 1})

Simplify

8 (- 1 \cdot x^{- 1 - 1}) : - \frac{8}{x ^{2}}

= - \frac{8}{x ^{2}}

f (x) = x^{- \frac{2}{5}}

\frac{d}{d x} ((e^{x}) (x + x x))

x \to 1 lim (2 x^{2} - 5 x + 1)

\int \frac{x ^{2}}{x ^{2} + 25} d x

\frac{\partial}{\partial x} (x y^{2})

What is the derivative of 8x^{-1} ?
The derivative of 8x^{-1} is -8/(x^2)
What is the first derivative of 8x^{-1} ?
The first derivative of 8x^{-1} is -8/(x^2)