What is the solution for (dy)/(dx)x+y= 1/(y^2) ?

The solution for (dy)/(dx)x+y= 1/(y^2) is y=(\sqrt[3]{-c_{1}+x^3})/x

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(dy)/(dx)x+y= 1/(y^2)

\frac{d y}{d x} x + y = \frac{1}{y ^{2}}

y = \frac{3 - c _{1} + x ^{3}}{x}

Solution steps

\frac{d y}{d x} x + y = \frac{1}{y ^{2}}

Solve separable ODE:

y = \frac{3 - c _{1} + x ^{3}}{x}

y = \frac{3 - c _{1} + x ^{3}}{x}

\int \frac{x ^{3} - x + 3}{x ^{2} + x - 2} d x

x \to - 1 - lim (∣ x - 1 ∣)

\int_{0}^{2} \frac{1}{2} x^{2} d x

\frac{d}{d x} (x^{4} - 18 x^{2} + 1)

\frac{d}{d t} (t^{3} - 1)

What is the solution for (dy)/(dx)x+y= 1/(y^2) ?
The solution for (dy)/(dx)x+y= 1/(y^2) is y=(\sqrt[3]{-c_{1}+x^3})/x