What is the derivative of f(x)=x^2-7 ?

The derivative of f(x)=x^2-7 is 2x

What is the first derivative of f(x)=x^2-7 ?

The first derivative of f(x)=x^2-7 is 2x

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derivative of

f (x) = x^{2} - 7

2 x

Solution steps

\frac{d}{d x} (x^{2} - 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (7)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (7) = 0

= 2 x - 0

Simplify

= 2 x

41 (6 t^{3} - 7)^{\frac{6}{5}}

\int_{0}^{\frac{π}{2}} t sin (2 t) d t

y = arctan (2 x)

cos (θ), sin (2 θ)

\frac{\partial}{\partial x} (sin (5 x + 2 y))

What is the derivative of f(x)=x^2-7 ?
The derivative of f(x)=x^2-7 is 2x
What is the first derivative of f(x)=x^2-7 ?
The first derivative of f(x)=x^2-7 is 2x