What is the derivative of-sin(2x*2) ?

The derivative of-sin(2x*2) is -4cos(2x)

What is the first derivative of-sin(2x*2) ?

The first derivative of-sin(2x*2) is -4cos(2x)

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\frac{d}{d x} (- sin (2 x) \cdot 2)

- 4 cos (2 x)

Solution steps

\frac{d}{d x} (- sin (2 x) \cdot 2)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 \frac{d}{d x} (sin (2 x))

Apply the chain rule:

cos (2 x) \frac{d}{d x} (2 x)

= cos (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= - 2 cos (2 x) \cdot 2

Simplify

= - 4 cos (2 x)

\int \frac{1}{x ^{2} \cdot 5 + x ^{2}} d x

y^{^{''}} - 8 y^{^{'}} + 18 y = 0, y (0) = - 4, y^{^{'}} (0) = 3

\int \frac{( 1 - cos ( 2 x ) )}{2} d x

\frac{sin ( θ )}{7} + \frac{c}{θ}

x \to 3 lim (\frac{π x}{4})

What is the derivative of-sin(2x*2) ?
The derivative of-sin(2x*2) is -4cos(2x)
What is the first derivative of-sin(2x*2) ?
The first derivative of-sin(2x*2) is -4cos(2x)