What is the first derivative of Ae^x ?

The first derivative of Ae^x is Ae^x

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derivative of Ae^x

\frac{d}{d x} (A e^{x})

A e^{x}

Solution steps

\frac{d}{d x} (A e^{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= A \frac{d}{d x} (e^{x})

Apply the common derivative:

\frac{d}{d x} (e^{x}) = e^{x}

= A e^{x}

\int (t^{3} + 2 t) sin (t) d t

\frac{d}{d x} (\frac{a - x}{a + x})

f (x) = ln (1 + e^{x}), at x = ln (2)

\int x (x - 3)^{2} d x

y = x^{4} - 4 x^{2} + 4, y = x^{2}