What is the derivative of y=8e^x+2/(\sqrt[3]{x)} ?

The derivative of y=8e^x+2/(\sqrt[3]{x)} is 8e^x-2/(3x^{4/3)}

What is the first derivative of y=8e^x+2/(\sqrt[3]{x)} ?

The first derivative of y=8e^x+2/(\sqrt[3]{x)} is 8e^x-2/(3x^{4/3)}

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derivative of

y = 8 e^{x} + \frac{2}{3 x}

8 e^{x} - \frac{2}{3 x ^{\frac{4}{3}}}

Solution steps

\frac{d}{d x} (8 e^{x} + \frac{2}{3 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (8 e^{x}) + \frac{d}{d x} (\frac{2}{3 x})

\frac{d}{d x} (8 e^{x}) = 8 e^{x}

\frac{d}{d x} (\frac{2}{3 x}) = - \frac{2}{3 x ^{\frac{4}{3}}}

= 8 e^{x} - \frac{2}{3 x ^{\frac{4}{3}}}

\int tan^{2} (θ) sec (θ) d θ

\int - 4 lo g_{7} (x) d x

\int x^{2} - 7 x d x

\int (3 sin (x)) d x

f (x) = \frac{x + 7}{x}

What is the derivative of y=8e^x+2/(\sqrt[3]{x)} ?
The derivative of y=8e^x+2/(\sqrt[3]{x)} is 8e^x-2/(3x^{4/3)}
What is the first derivative of y=8e^x+2/(\sqrt[3]{x)} ?
The first derivative of y=8e^x+2/(\sqrt[3]{x)} is 8e^x-2/(3x^{4/3)}