What is (\partial)/(\partial y)(cos(2xy)) ?

The answer to (\partial)/(\partial y)(cos(2xy)) is -sin(2xy)*2x

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(\partial)/(\partial y)(cos(2xy))

\frac{\partial}{\partial y} (cos (2 x y))

- sin (2 x y) \cdot 2 x

Solution steps

\frac{\partial}{\partial y} (cos (2 x y))

Treat

x

as a constant

Apply the chain rule:

- sin (2 x y) \frac{\partial}{\partial y} (2 x y)

= - sin (2 x y) \frac{\partial}{\partial y} (2 x y)

\frac{\partial}{\partial y} (2 x y) = 2 x

= - sin (2 x y) \cdot 2 x

g (x) = 9 - 2

\int_{- 1}^{1} \frac{5 x}{( x + 3 ) ^{2}} d x

\int \frac{1}{1 + 4 y ^{2}} d y

x \to - 4 lim (7^{x})

\int_{2}^{6} ln (5 x) d x

What is (\partial)/(\partial y)(cos(2xy)) ?
The answer to (\partial)/(\partial y)(cos(2xy)) is -sin(2xy)*2x