What is the integral from 1 to infinity of 7/(x^3) ?

The integral from 1 to infinity of 7/(x^3) is 7/2

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integral from 1 to infinity of 7/(x^3)

\int_{1}^{\infty} \frac{7}{x ^{3}} d x

\frac{7}{2}

Decimal

3.5

Solution steps

\int_{1}^{\infty} \frac{7}{x ^{3}} d x

Compute the indefinite integral:

\int \frac{7}{x ^{3}} d x = - \frac{7}{2 x ^{2}} + C

Compute the boundaries:

\int_{1}^{\infty} \frac{7}{x ^{3}} d x = 0 - (- \frac{7}{2})

= 0 - (- \frac{7}{2})

Simplify

= \frac{7}{2}

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What is the integral from 1 to infinity of 7/(x^3) ?
The integral from 1 to infinity of 7/(x^3) is 7/2