What is the sum from n=-4 to infinity of ((-4)/9)^n ?

The sum from n=-4 to infinity of ((-4)/9)^n is converges

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sum from n=-4 to infinity of ((-4)/9)^n

n = - 4 \sum \infty (\frac{- 4}{9})^{n}

converges

Solution steps

n = - 4 \sum \infty (\frac{- 4}{9})^{n}

Apply Series Ratio Test:

converges

= converges

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n = 1 \sum \infty \frac{1}{n}

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What is the sum from n=-4 to infinity of ((-4)/9)^n ?
The sum from n=-4 to infinity of ((-4)/9)^n is converges