What is (\partial)/(\partial y)(xy+yz+xz) ?

The answer to (\partial)/(\partial y)(xy+yz+xz) is x+z

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(\partial)/(\partial y)(xy+yz+xz)

\frac{\partial}{\partial y} (x y + yz + x z)

x + z

Solution steps

\frac{\partial}{\partial y} (x y + yz + x z)

Treat

x, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x y) + \frac{\partial}{\partial y} (yz) + \frac{\partial}{\partial y} (x z)

\frac{\partial}{\partial y} (x y) = x

\frac{\partial}{\partial y} (yz) = z

\frac{\partial}{\partial y} (x z) = 0

= x + z + 0

Simplify

= x + z

x \to (\frac{π}{2}) - lim (tan (x))

\frac{\partial}{\partial x} (x^{m} y^{n})

\int \frac{x}{3 + x} d x

\frac{e ^{2}}{x ^{2} - 2 x}

\frac{( 2 )}{sin ( x ) + cos ( x )}

What is (\partial)/(\partial y)(xy+yz+xz) ?
The answer to (\partial)/(\partial y)(xy+yz+xz) is x+z