What is the integral of (sec^2(x)+3) ?

The integral of (sec^2(x)+3) is tan(x)+3x+C

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integral of (sec^2(x)+3)

\int (sec^{2} (x) + 3) d x

tan (x) + 3 x + C

Solution steps

\int sec^{2} (x) + 3 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int sec^{2} (x) d x + \int 3 d x

\int sec^{2} (x) d x = tan (x)

\int 3 d x = 3 x

= tan (x) + 3 x

Add a constant to the solution

= tan (x) + 3 x + C

\frac{d}{d x} (\frac{( 3 x + 3 )}{4 e ^{x}})

\int e x d x

y^{^{''}} + 4 y^{^{'}} + 4 y = 0

\frac{d}{d x} (\frac{24}{( 1 - x ) ^{5}})

(ln ∣ x + 2 ∣)^{7}

What is the integral of (sec^2(x)+3) ?
The integral of (sec^2(x)+3) is tan(x)+3x+C