What is the derivative of f(x)= 2/(3x^2) ?

The derivative of f(x)= 2/(3x^2) is -4/(3x^3)

What is the first derivative of f(x)= 2/(3x^2) ?

The first derivative of f(x)= 2/(3x^2) is -4/(3x^3)

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derivative of

f (x) = \frac{2}{3 x ^{2}}

- \frac{4}{3 x ^{3}}

Solution steps

\frac{d}{d x} (\frac{2}{3 x ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{2}{3} \frac{d}{d x} (\frac{1}{x ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{2}{3} \frac{d}{d x} (x^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{2}{3} (- 2 x^{- 2 - 1})

Simplify

\frac{2}{3} (- 2 x^{- 2 - 1}) : - \frac{4}{3 x ^{3}}

= - \frac{4}{3 x ^{3}}

n = 1 \sum \infty 2^{- 2 n}

y^{^{''}} + 4 y^{^{'}} + 4 y = 2 x + 6

y^{^{''}} - 2 y^{^{'}} + 2 y = e^{x} sin (x)

\int 0.06 \cdot e^{\frac{t}{300}} d t

What is the derivative of f(x)= 2/(3x^2) ?
The derivative of f(x)= 2/(3x^2) is -4/(3x^3)
What is the first derivative of f(x)= 2/(3x^2) ?
The first derivative of f(x)= 2/(3x^2) is -4/(3x^3)