What is the solution for xy+y^2+x^2-x^2y^'=0 ?

The solution for xy+y^2+x^2-x^2y^'=0 is y=tan(ln(x)+c_{1})x

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xy+y^2+x^2-x^2y^'=0

x y + y^{2} + x^{2} - x^{2} y^{^{'}} = 0

y = tan (ln (x) + c_{1}) x

Solution steps

x y + y^{2} + x^{2} - x^{2} y^{'} (x) = 0

Solve using substitution:

y = tan (ln (x) + c_{1}) x

y = tan (ln (x) + c_{1}) x

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\frac{d y}{d x} - 2 y = 3 x

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What is the solution for xy+y^2+x^2-x^2y^'=0 ?
The solution for xy+y^2+x^2-x^2y^'=0 is y=tan(ln(x)+c_{1})x