What is the derivative of sqrt(x)+tan(x) ?

The derivative of sqrt(x)+tan(x) is 1/(2sqrt(x))+sec^2(x)

What is the first derivative of sqrt(x)+tan(x) ?

The first derivative of sqrt(x)+tan(x) is 1/(2sqrt(x))+sec^2(x)

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derivative of

x + tan (x)

\frac{1}{2 x} + sec^{2} (x)

Solution steps

\frac{d}{d x} (x + tan (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x) + \frac{d}{d x} (tan (x))

\frac{d}{d x} (x) = \frac{1}{2 x}

\frac{d}{d x} (tan (x)) = sec^{2} (x)

= \frac{1}{2 x} + sec^{2} (x)

\int \frac{x ^{2}}{x ^{2} + y ^{2}} d y

\int x \frac{1}{1} d x

\frac{d}{d t} (b sin (wt))

\frac{d}{d x} (w \cdot sin (w c t) \cdot cos (w x))

\frac{\partial}{\partial x} (\frac{3}{x})

What is the derivative of sqrt(x)+tan(x) ?
The derivative of sqrt(x)+tan(x) is 1/(2sqrt(x))+sec^2(x)
What is the first derivative of sqrt(x)+tan(x) ?
The first derivative of sqrt(x)+tan(x) is 1/(2sqrt(x))+sec^2(x)